1/3(x+4)^2=12

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Solution for 1/3(x+4)^2=12 equation: 


x in (-oo:+oo)

(1/3)*(x+4)^2 = 12 // - 12

(1/3)*(x+4)^2-12 = 0

1/3*(x+4)^2-12 = 0

1/3*(x+4)^2-12 = 0

1/3*x^2+8/3*x-20/3 = 0

1/3*x^2+8/3*x-20/3 = 0

1/3*(x^2+8*x-20) = 0

x^2+8*x-20 = 0

DELTA = 8^2-(-20*1*4)

DELTA = 144

DELTA > 0

x = (144^(1/2)-8)/(1*2) or x = (-144^(1/2)-8)/(1*2)

x = 2 or x = -10

1/3*(x+10)*(x-2) = 0

1/3*(x+10)*(x-2) = 0

( x+10 )

x+10 = 0 // - 10

x = -10

( x-2 )

x-2 = 0 // + 2

x = 2

x in { -10, 2 }

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